7x^2+x-60=0

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Solution for 7x^2+x-60=0 equation:



7x^2+x-60=0
a = 7; b = 1; c = -60;
Δ = b2-4ac
Δ = 12-4·7·(-60)
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1681}=41$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-41}{2*7}=\frac{-42}{14} =-3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+41}{2*7}=\frac{40}{14} =2+6/7 $

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